Type an input and write what you think is the output . Each problem is converted to Web Assembly, so any possible input will show the corresponding output. Only correct predictions count.
Locked until you have predicted 3 outputs correctly.
| 1 | bool solution(int n, const vector<vector<int>>& pairs) { |
| 2 | |
| 3 | vector<vector<int>> unlocks(n); |
| 4 | vector<int> waiting(n, 0); |
| 5 | |
| 6 | for (const auto& p : pairs) { |
| 7 | unlocks[p[1]].push_back(p[0]); |
| 8 | waiting[p[0]]++; |
| 9 | } |
| 10 | |
| 11 | queue<int> ready; |
| 12 | |
| 13 | for (int i = 0; i < n; i++) { |
| 14 | if (waiting[i] == 0) { |
| 15 | ready.push(i); |
| 16 | } |
| 17 | } |
| 18 | |
| 19 | int taken = 0; |
| 20 | |
| 21 | while (!ready.empty()) { |
| 22 | |
| 23 | int course = ready.front(); |
| 24 | ready.pop(); |
| 25 | taken++; |
| 26 | |
| 27 | for (int other : unlocks[course]) { |
| 28 | |
| 29 | waiting[other]--; |
| 30 | |
| 31 | if (waiting[other] == 0) { |
| 32 | ready.push(other); |
| 33 | } |
| 34 | } |
| 35 | } |
| 36 | |
| 37 | return taken == n; |
| 38 | } |
Names have been stripped. The signature is the only clue you get for free. Compiled as C++20 with the standard headers and using namespace std; already in scope.